9c^2-18c+8=8

Solution for 9c^2-18c+8=8 equation:

9c^2-18c+8=8

We move all terms to the left:

9c^2-18c+8-(8)=0

We add all the numbers together, and all the variables

9c^2-18c=0

a = 9; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·9·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*9}=\frac{0}{18}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*9}=\frac{36}{18}
=2
$